The reaction of the electrophilic transition metal iridium with tellurium, indium, and bromine resulted in black, shiny crystals with the composition [Ir₂Te₁₄Br₁₂]₂(InBr ₄)₂. X-ray diffraction on single-crystals revealed a triclinic structure (space group P1) that contains two crystallographically distinct, centrosymmetric clusters, (Te₁₀)[Ir(TeBr₃) ₂]₂⁺ and (Te₁₀)[Ir(TeBr ₄)(TeBr₂)]₂⁺, as well as two tetrahedral InBr₄^- anions per unit cell. The center of the positively charged cluster is a Te₁₀^·- radical anion. This biconvex tricyclo[5.1.1.1^{3, 5}] unit consists of two angulated Te₄ rings that are linked by two almost linear μ-Te bridges. The radical causes an intense single ESR signal at g = 1.999. Molecular DFT-calculations show that the unpaired electron populates an orbital of the Te₁₀-unit. Computational variation of the number of electrons causes noticeable variations in the Te-Te distances, providing strong evidence for the Te₁₀^·- radical. The decatellurium unit coordinates two iridium(III) cations as a bridging bis-tetradentate ligand. Two terminal bromidotellurate(II) groups complete the slightly distorted octahedral coordination of each transition metal atom. The two [IrTe₆] polyhedra share a common edge. The constitutions of the terminal ligands differ, including only TeBr₃^- anions in one type of clusters, but a combination of TeBr₄^2- and TeBr₂ groups in the other. The coordinating tellurium atoms of the central Te₁₀ ^·- and of the terminal groups act as electron pair donors, thereby fulfilling the 18-electron-rule for the iridium(III) cations.